|  | 
 
| 对比两个文本,删除a文本里含有b文本某行字符一行 比如b文本为
 2345
 78965
 erty
 hjkul
 444
 785
 ghj
 45678
 a文本为
 2345fghjyrf
 2345-edfghj
 ety56783
 ghrffhfh456
 4565467576767
 78965fgrtyh
 执行后得到文本应该为
 ety56783
 ghrffhfh456
 4565467576767
 
 
 
 复制代码copy /y a.txt c.txt >nul
for /f "delims=" %%a in (b.txt) do (type c.txt|find "%%a">nul&&(type c.txt|find /v "%%a")>temp.txt
move /y temp.txt c.txt >nul 2>nul
)
exit /b
 | 
 |